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Gil Amarth · 05-18-2013 05:51 AM

The script is very simple, 1 day it´s 86400 seconds, so you have to divide the the total amount of seconds to how many seconds a day has.

Then you have to calculate the rest of the division, f_division_resto does that. It´s only maths.
With the rest you repeat the operation, 1 hour has 3600 seconds, and repeat.
If you want months, and weeks.

Code:

[FUNCTION F_FORMAT_TIME]

LOCAL.MONTHS = <ARGS>/2592000    // Months of 30 days

LOCAL.REST = <F_DIVISION_REST <ARGS>,2592000>

LOCAL.WEEKS = <LOCAL.REST>/604800

LOCAL.REST = <F_DIVISION_REST <LOCAL.REST>,604800>

LOCAL.DAYS = <LOCAL.REST>/86400

LOCAL.REST = <F_DIVISION_REST <LOCAL.REST>,86400>

LOCAL.HOURS = <LOCAL.REST>/3600

LOCAL.REST = <F_DIVISION_REST <LOCAL.REST>,3600>

LOCAL.MINUTES = <LOCAL.REST>/60

LOCAL.REST = <F_DIVISION_REST <LOCAL.REST>,60>    // Seconds

SYSMESSAGE @00 <dLOCAL.MONTHS> Months, <dLOCAL.WEEKS> Weeks, <dLOCAL.DAYS> Days, <dLOCAL.HOURS> Hours, <dLOCAL.MINUTES> Minutes, <dLOCAL.REST> seconds

Code:

[FUNCTION f_division_rest]    // (DIVIDEND, DIVISOR); Returns (REST)

LOCAL.LOOPS = <ARGV[0]> / <ARGV[1]>

LOCAL.ELAPSED = <LOCAL.LOOPS> * <ARGV[1]>

LOCAL.REST = <EVAL <ARGV[0]> - <LOCAL.ELAPSED>>

RETURN <LOCAL.REST>

Then, you can use F_FORMAT_TIME <TAG.TIME>, and voilá.

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